Optimal. Leaf size=185 \[ -\frac {c^3 \log \left (2-\frac {2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{d}-\frac {c^2 \left (a+b \tanh ^{-1}(c x)\right )}{d x}-\frac {a+b \tanh ^{-1}(c x)}{3 d x^3}+\frac {c \left (a+b \tanh ^{-1}(c x)\right )}{2 d x^2}+\frac {b c^3 \text {Li}_2\left (\frac {2}{c x+1}-1\right )}{2 d}+\frac {4 b c^3 \log (x)}{3 d}-\frac {b c^3 \tanh ^{-1}(c x)}{2 d}+\frac {b c^2}{2 d x}-\frac {2 b c^3 \log \left (1-c^2 x^2\right )}{3 d}-\frac {b c}{6 d x^2} \]
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Rubi [A] time = 0.35, antiderivative size = 185, normalized size of antiderivative = 1.00, number of steps used = 17, number of rules used = 11, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.550, Rules used = {5934, 5916, 266, 44, 325, 206, 36, 29, 31, 5932, 2447} \[ \frac {b c^3 \text {PolyLog}\left (2,\frac {2}{c x+1}-1\right )}{2 d}-\frac {c^2 \left (a+b \tanh ^{-1}(c x)\right )}{d x}-\frac {c^3 \log \left (2-\frac {2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{d}+\frac {c \left (a+b \tanh ^{-1}(c x)\right )}{2 d x^2}-\frac {a+b \tanh ^{-1}(c x)}{3 d x^3}-\frac {2 b c^3 \log \left (1-c^2 x^2\right )}{3 d}+\frac {b c^2}{2 d x}+\frac {4 b c^3 \log (x)}{3 d}-\frac {b c^3 \tanh ^{-1}(c x)}{2 d}-\frac {b c}{6 d x^2} \]
Antiderivative was successfully verified.
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Rule 29
Rule 31
Rule 36
Rule 44
Rule 206
Rule 266
Rule 325
Rule 2447
Rule 5916
Rule 5932
Rule 5934
Rubi steps
\begin {align*} \int \frac {a+b \tanh ^{-1}(c x)}{x^4 (d+c d x)} \, dx &=-\left (c \int \frac {a+b \tanh ^{-1}(c x)}{x^3 (d+c d x)} \, dx\right )+\frac {\int \frac {a+b \tanh ^{-1}(c x)}{x^4} \, dx}{d}\\ &=-\frac {a+b \tanh ^{-1}(c x)}{3 d x^3}+c^2 \int \frac {a+b \tanh ^{-1}(c x)}{x^2 (d+c d x)} \, dx-\frac {c \int \frac {a+b \tanh ^{-1}(c x)}{x^3} \, dx}{d}+\frac {(b c) \int \frac {1}{x^3 \left (1-c^2 x^2\right )} \, dx}{3 d}\\ &=-\frac {a+b \tanh ^{-1}(c x)}{3 d x^3}+\frac {c \left (a+b \tanh ^{-1}(c x)\right )}{2 d x^2}-c^3 \int \frac {a+b \tanh ^{-1}(c x)}{x (d+c d x)} \, dx+\frac {(b c) \operatorname {Subst}\left (\int \frac {1}{x^2 \left (1-c^2 x\right )} \, dx,x,x^2\right )}{6 d}+\frac {c^2 \int \frac {a+b \tanh ^{-1}(c x)}{x^2} \, dx}{d}-\frac {\left (b c^2\right ) \int \frac {1}{x^2 \left (1-c^2 x^2\right )} \, dx}{2 d}\\ &=\frac {b c^2}{2 d x}-\frac {a+b \tanh ^{-1}(c x)}{3 d x^3}+\frac {c \left (a+b \tanh ^{-1}(c x)\right )}{2 d x^2}-\frac {c^2 \left (a+b \tanh ^{-1}(c x)\right )}{d x}-\frac {c^3 \left (a+b \tanh ^{-1}(c x)\right ) \log \left (2-\frac {2}{1+c x}\right )}{d}+\frac {(b c) \operatorname {Subst}\left (\int \left (\frac {1}{x^2}+\frac {c^2}{x}-\frac {c^4}{-1+c^2 x}\right ) \, dx,x,x^2\right )}{6 d}+\frac {\left (b c^3\right ) \int \frac {1}{x \left (1-c^2 x^2\right )} \, dx}{d}-\frac {\left (b c^4\right ) \int \frac {1}{1-c^2 x^2} \, dx}{2 d}+\frac {\left (b c^4\right ) \int \frac {\log \left (2-\frac {2}{1+c x}\right )}{1-c^2 x^2} \, dx}{d}\\ &=-\frac {b c}{6 d x^2}+\frac {b c^2}{2 d x}-\frac {b c^3 \tanh ^{-1}(c x)}{2 d}-\frac {a+b \tanh ^{-1}(c x)}{3 d x^3}+\frac {c \left (a+b \tanh ^{-1}(c x)\right )}{2 d x^2}-\frac {c^2 \left (a+b \tanh ^{-1}(c x)\right )}{d x}+\frac {b c^3 \log (x)}{3 d}-\frac {b c^3 \log \left (1-c^2 x^2\right )}{6 d}-\frac {c^3 \left (a+b \tanh ^{-1}(c x)\right ) \log \left (2-\frac {2}{1+c x}\right )}{d}+\frac {b c^3 \text {Li}_2\left (-1+\frac {2}{1+c x}\right )}{2 d}+\frac {\left (b c^3\right ) \operatorname {Subst}\left (\int \frac {1}{x \left (1-c^2 x\right )} \, dx,x,x^2\right )}{2 d}\\ &=-\frac {b c}{6 d x^2}+\frac {b c^2}{2 d x}-\frac {b c^3 \tanh ^{-1}(c x)}{2 d}-\frac {a+b \tanh ^{-1}(c x)}{3 d x^3}+\frac {c \left (a+b \tanh ^{-1}(c x)\right )}{2 d x^2}-\frac {c^2 \left (a+b \tanh ^{-1}(c x)\right )}{d x}+\frac {b c^3 \log (x)}{3 d}-\frac {b c^3 \log \left (1-c^2 x^2\right )}{6 d}-\frac {c^3 \left (a+b \tanh ^{-1}(c x)\right ) \log \left (2-\frac {2}{1+c x}\right )}{d}+\frac {b c^3 \text {Li}_2\left (-1+\frac {2}{1+c x}\right )}{2 d}+\frac {\left (b c^3\right ) \operatorname {Subst}\left (\int \frac {1}{x} \, dx,x,x^2\right )}{2 d}+\frac {\left (b c^5\right ) \operatorname {Subst}\left (\int \frac {1}{1-c^2 x} \, dx,x,x^2\right )}{2 d}\\ &=-\frac {b c}{6 d x^2}+\frac {b c^2}{2 d x}-\frac {b c^3 \tanh ^{-1}(c x)}{2 d}-\frac {a+b \tanh ^{-1}(c x)}{3 d x^3}+\frac {c \left (a+b \tanh ^{-1}(c x)\right )}{2 d x^2}-\frac {c^2 \left (a+b \tanh ^{-1}(c x)\right )}{d x}+\frac {4 b c^3 \log (x)}{3 d}-\frac {2 b c^3 \log \left (1-c^2 x^2\right )}{3 d}-\frac {c^3 \left (a+b \tanh ^{-1}(c x)\right ) \log \left (2-\frac {2}{1+c x}\right )}{d}+\frac {b c^3 \text {Li}_2\left (-1+\frac {2}{1+c x}\right )}{2 d}\\ \end {align*}
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Mathematica [A] time = 0.43, size = 172, normalized size = 0.93 \[ \frac {-6 a c^3 x^3 \log (x)+6 a c^3 x^3 \log (c x+1)-6 a c^2 x^2+3 a c x-2 a+3 b c^3 x^3 \text {Li}_2\left (e^{-2 \tanh ^{-1}(c x)}\right )+b c^3 x^3+3 b c^2 x^2+8 b c^3 x^3 \log \left (\frac {c x}{\sqrt {1-c^2 x^2}}\right )-b \tanh ^{-1}(c x) \left (3 c^3 x^3+6 c^3 x^3 \log \left (1-e^{-2 \tanh ^{-1}(c x)}\right )+6 c^2 x^2-3 c x+2\right )-b c x}{6 d x^3} \]
Warning: Unable to verify antiderivative.
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fricas [F] time = 0.61, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {b \operatorname {artanh}\left (c x\right ) + a}{c d x^{5} + d x^{4}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {b \operatorname {artanh}\left (c x\right ) + a}{{\left (c d x + d\right )} x^{4}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.06, size = 328, normalized size = 1.77 \[ -\frac {a}{3 d \,x^{3}}-\frac {c^{2} a}{d x}+\frac {c a}{2 d \,x^{2}}-\frac {c^{3} a \ln \left (c x \right )}{d}+\frac {c^{3} a \ln \left (c x +1\right )}{d}-\frac {b \arctanh \left (c x \right )}{3 d \,x^{3}}-\frac {c^{2} b \arctanh \left (c x \right )}{d x}+\frac {c b \arctanh \left (c x \right )}{2 d \,x^{2}}-\frac {c^{3} b \arctanh \left (c x \right ) \ln \left (c x \right )}{d}+\frac {c^{3} b \arctanh \left (c x \right ) \ln \left (c x +1\right )}{d}-\frac {b c}{6 d \,x^{2}}+\frac {b \,c^{2}}{2 d x}+\frac {4 c^{3} b \ln \left (c x \right )}{3 d}-\frac {5 c^{3} b \ln \left (c x -1\right )}{12 d}-\frac {11 c^{3} b \ln \left (c x +1\right )}{12 d}+\frac {c^{3} b \dilog \left (c x \right )}{2 d}+\frac {c^{3} b \dilog \left (c x +1\right )}{2 d}+\frac {c^{3} b \ln \left (c x \right ) \ln \left (c x +1\right )}{2 d}-\frac {c^{3} b \ln \left (c x +1\right )^{2}}{4 d}+\frac {c^{3} b \ln \left (-\frac {c x}{2}+\frac {1}{2}\right ) \ln \left (c x +1\right )}{2 d}-\frac {c^{3} b \ln \left (-\frac {c x}{2}+\frac {1}{2}\right ) \ln \left (\frac {1}{2}+\frac {c x}{2}\right )}{2 d}-\frac {c^{3} b \dilog \left (\frac {1}{2}+\frac {c x}{2}\right )}{2 d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {1}{6} \, {\left (\frac {6 \, c^{3} \log \left (c x + 1\right )}{d} - \frac {6 \, c^{3} \log \relax (x)}{d} - \frac {6 \, c^{2} x^{2} - 3 \, c x + 2}{d x^{3}}\right )} a + \frac {1}{2} \, b \int \frac {\log \left (c x + 1\right ) - \log \left (-c x + 1\right )}{c d x^{5} + d x^{4}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {a+b\,\mathrm {atanh}\left (c\,x\right )}{x^4\,\left (d+c\,d\,x\right )} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {\int \frac {a}{c x^{5} + x^{4}}\, dx + \int \frac {b \operatorname {atanh}{\left (c x \right )}}{c x^{5} + x^{4}}\, dx}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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